PROCESSES AND PROPERTIES OF AIR

Dry-bulb, wet-bulb, dew-point temperatures, relative humidity-these terms are so closely related that if two properties are known, all others shown in the figure below may be read from the chart. When air is saturated, dry-bulb, wet-bulb, and dew-point temperatures are identical. (See Example 2.)

Enthalpy of air for any given condition is the enthalpy at saturation corrected by the enthalpy deviation due to the air not being in a saturated state. The enthalpy (h) in Btu per pound of dry air is the enthalpy at the saturation hwb plus the enthalpy deviation hd See Example 2.

H + hwb + hd

If the air's moisture content increases or decreases in a psychometric process, the heat added (q) or removed (-q) is the difference between the enthalpy of the final or leaving air hla and the initial or entering air hea minus the enthalpy of the moisture (water in liquid or ice state) added hw or rejected hw. See Examples 4 and 5.

q = hla - hea - hw

The enthalpy of added or rejected moisture is shown in the small graphs at the top of the chart.

Enthalpy of added or rejected moisture and enthalpy deviation are usually omitted in applications not requiring precise results- for example, comfort air conditioning. Errors due to omissions for wet-bulb temperatures below 32°F is much larger than for omissions above 32°F.

Sensible heat factor. This is part of certain calculations for installing air condi-tioning equipment. A scale along the right side of the figure in Example 4 below used with an origin at 80°F dry-bulb temperature and 50 percent rh provide a reasonable heat factor value. See Example 4.

Barometric pressures. In comfort air conditioning, a mercury reading of one inch or less either above or below the standard 29.92 inches of mercury is considered a standard reading.

When dry-bulb and dew-point temperatures are known for air at non-standard barometric pressures, values of percent rh and grains of moisture per cubic foot are correct on a standard chart. But for given dry-bulb and wet-bulb readings at non-standard barometric pressures, all properties must be corrected.

INTERPRETING THE AIR CONDITIONING CHARTS

Generally, in graphic presentations, humidifying is shown by an upward line and dehumidifying is shown by a downward line.

Heating and cooling air without changes in moisture content involve only a change in sensible heat and appear as a horizontal line, to right or left respectively. Changes occur in dry-bulb, wet-bulb, rh, and enthalpy. Specific humidity and dew-point temperature remain constant.

In heating and humidifying, both sensible heat and specific humidity increase-shown as a line sloping upward and to the right. Changes occur in dry-bulb, wet-bulb, dew-point temperatures, and enthalpy. A difference in rh depends on the slope of the line.

For cooling and dehumidifying, both sensible heat and specific humidity decrease, so the line slopes downward and to the left. Dry-bulb, wet-bulb, dew-point temperatures, and enthalpy all change. Changes in rh are dependent on the slope of the line.

Evaporative cooling refers to air brought in contact with spray water at a temperature equal to the wet-bulb temperature of the air. The process takes place upward along the wet-bulb line. As sensible heat of the initial air vaporizes the water, the air's dry-bulb temperature falls. The sensible heat used to vaporize the water enters the air as latent heat in added vapor; thus no heat is added or removed. Wet-bulb temperature remains constant. Dew-point temperature, rh, specific humidity, and enthalpy increase. (In most evaporative cooling installations, heat may be added or removed during the process due to outside sources, this amount is usually negligible.)

In chemical dehydration, the air that contacts the chemical either adsorbs or absorbs moisture from the air. Thus in this energy constant process, heat is liberated and added to the air- and this amount is basically equal to the latent heat of vaporization of the moisture removed. Indicated by a downward sloping line approximating the wet-bulb line, the slope of the chemical dehydration line may be either slightly greater or less than the wet-bulb line, depending on if heat is stored, liberated, or absorbed.

AIR CONDITIONING PROCESSES such as heating, cooling, humidifying and dehumidifying may be shown graphically on the chart. See Figure 1.

EXAMPLE 1. Reading Properties of Air

Given		DB = 70°F		% RH DP
		Find:		Volume
		WB = 60°F		GR of moisture per lb dry air GR of moisture per cu. ft.

Locate point of intersection on the chart of vertical line representing 70°DB and oblique line representing 60°WB. All values are read from this point of intersection.

Interpolate between relative humidity lines on 70°DB line, read RH = 56%.

Follow horizontal line left to saturation curve, read DP = 53.6°F.

Interpolate between lines representing cubic feet per pound of dry air, read v = 13.53 cu ft.

Follow horizontal line to right, read grains of moisture per pound of dry air, W=61.4 gr.

Grains of moisture per pound of dry air (61.4) divided by cubic feet per pound of dry air (13.53) = 4.54 gr per cu ft.

EXAMPLE 2. Reading properties of Air

Given		DB = 50%		DB DP Gr. of moisture per lb. dry air Enthalpy
		Find:
		WB = 60°F

Locate point of intersection on the chart of 50% RH line and oblique line representing 60°WB. All values are read from this point.

Follow vertical line downward to dry-bulb temperature scale, read DB = 71.9°F.

Follow horizontal line left to saturation curve, read DP = 52.3°F.

Follow horizontal line to right, read grains of moisture per pound of dry air, W = 58.4 gr.

Follow wet-bulb line to "Enthalpy at saturation" scale and read Hwb = 26.46 Btu. Read enthalpy deviation for point of intersection hd = -.08 Btu. Enthalpy of air at given condition h= hwb + hd = 26.46 + (-.08) = 26.38 Btu per lb of dry air.

EXAMPLE 3. Heating process
(no change in moisture content)

Locate the condition initial air on the chart.
Follow horizontal line to 75° DB.
Read:RH=15% : WB=51.5°F : DB=25.2°F.

Exact Solution - Head added:

Read enthalpy at saturation initial air hcwb = 10.10 Btu
Read enthalpy deviation initial air hcd = 0.06 Btu
Enthalpy of initial air hca = hcwb + hcd = 10.10 + .06 = 10.16 Btu
Read enthalpy at saturation of final air hlwb = 21.14 Btu

Read enthalpy deviation of final air hld = 0.10 Btu
Enthalpy of final air hla = hlwb + hld = 21.14 + (-0.10) = 21.04 Btu
Heat added q = hla - hca =21.04 - 10.16 = 10.88 Btu per lb of dry air

Approximate Solution - Head added:

q = hlwb - hcwb = 21.14 - 10.10 = 11.04 Btu per lb of dry air.
The approximate solution is 1.5% higher than exact solution.

EXAMPLE 4. Cooling and Dehumidifying Process

(a) Moisture rejected as water condensate

Locate initial and final conditions of air on chart.

Read: h_cwb = 33.25 Btu
            h_lwb = 23.22Btu
            h_cd = -0.12 Btu
            h_ld = -0.01 Btu
            h_ca = 33.25 + (-0.12) = 33.13 Btu
            h_la = 23.22 + (-0.01) = 23.21 Btu

Read grains of moisture in initial air W_ea= 84

Read grains of moisture in final air W_la = 63 w = W_la – W_ea = 63 – 84 = 21 (moisture rejected)

Read enthalpy of rejected moisture (h_w) from diagrams at top of chart for 21 gr grains and 55 F = -0.8 Btu.

Exact Solution – Heat removed:
q = h_la – h_ea – h_w = 23.21 – 33.13 – (0.08) =
-9.84 Btu per lb dry air.

Approximate Solution – Heat removed:
q = h_lwb – h_cwb  = 23.22 – 33.25 = -10.03 Btu per lb dry air.

Approximate solution is 1.9% higher than exact solution.

To determine Sensible Heat Factor, draw a line between initial and final conditions.  Draw a line parallel to this line from reference point (80 DB, 50RH) to Sensible Heat Factor scale, read SHF = 0.68.

EXAMPLE 5. Mixture of Air



Locate on chart conditions of inside and entering air. Draw line connecting two points. Measure off distance equal to ¼ of line, starting from inside air condition. Point thus established represents condition of mixture of inside and entering air.

Read properties of mixture:

DB = 80°F, WB = 65.6°F, h = 30.50 + (-0.11) = 30.39 Btu Moisture content (W) = 71.3 gr per lb of dry air.

When air quantities being mixed are at widely different temperatures, the above method is slightly in error. For exact solution calculate properties of mixture on basis of specific humidity and enthalpy.

Dehumidifiers & Dryers
Plastic Auxiliary Equipment